Ex parte OXMAN - Page 4




          Appeal No. 95-0992                                                          
          Application 08/014,104                                                      


          restorations (col. 3, lines 50-61).  Stoner states that he                  
          believes that the improved corrosion results from mercury from              
          the bulk of the amalgam diffusing into the metal of the lining              
          and forming an alloy zone free of tin atoms next to the cavity              
          surfaces (col. 3, lines 61-64).  Since no tin atoms are present             
          next to the cavity surfaces, Stoner states, there is no oxidation           
          in this region (col. 3, lines 64-66).                                       
               Appellant’s specification (page 5, lines 1-2) states that              
          the primary components of dental amalgams include metallic                  
          mercury, silver and tin.  The following table shows the                     
          potentials for oxidation-reduction half-reactions at 25EC for               
          these elements taken from the CRC Handbook, pages D-158 to D-159.           
          Following these potentials in the table are the potentials for              
          platinum and gold, which are two of the elements disclosed by               
          Stoner.  The oxidation strengths increase in the downward                   
          direction in the table, as EE increases.                                    
          EE                                                                          
          (volts)                                                                     
          Sn  + 2e  = Sn                     -0.1364+2    -                                                       
          Ag  + e   = Ag                       .7996+   -                                                         
          Hg  + 2e = Hg                       .851+2    -                                                       
          Pt  + 2e  = Pt                     -1.2+2    -                                                       
          Au   + e  = Au                      1.68+   -                                                         
               The first three entries in the table indicate that an                  

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