Ex parte CORBIN et al. - Page 14




          Appeal No. 1995-4851                                                        
          Application 08/167,656                                                      


               The examiner argues that appellants’ claims and those of               
          Corbin “differ only in the starting materials used” (answer,                
          page 3).  As pointed out by appellants (brief, page 29), the                
          examiner is incorrect.  The product made by Corbin’s process,               
          1,1,1,2-tetrafluoroethane, is a hydrofluorocarbon, and differs              
          from the hydrochlorofluorocarbon, 2-chloro-1,1,1-                           
          trifluoroethane, made by appellants’ process.                               
               The examiner argues that Manzer discloses the equivalence              
          of various saturated and unsaturated starting materials in a                
          process which is similar to that of Corbin (answer, page 3).                
          Manzer                                                                      
          teaches that his starting material can be a trihaloethene,                  
          CClX=CHCl, and/or a tetrahaloethane, CCl XCH Cl, where, in both             
                                                  2   2                               
          formulas, X is Cl or F.  The formula for Manzer’s                           
          trihaloethene includes CCl =CHCl and CClF=CHCl, which can be                
                                    2                                                 
          appellants’ starting materials.  Manzer’s tetrahaloethane                   
          includes CH ClCCl  and CH ClCCl F, which fall within the2    3       2     2                                             
          formulas for Corbin’s tetrahaloethane starting materials,                   
          i.e., CH ClCX  and CH XCClX , where, in both formulas, X is Cl2   3       2     2                                                 
          or F.  The examiner’s argument apparently is that given the                 


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